HarpyEagle -> RE: Stacking Multiple Artillery and no penalty (2/14/2016 3:48:16 PM)
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quote:
However, I am able to stack multiple artillery units that each have 10 artillery in each unit (100 stack points), e.g., 3 of these for 300 stack points. I do understand that once I do an artillery strike, the hex attacked will show that you did an artillery barrage on that hex, and checking the hex you can see that, e.g., the "BSART" data box will show 100. However, what if I stack 3 units, each with 100 stack points for a total of 300 in one hex and spread any barrage out to 3 different hexes with no more than 100 BSART on any one hex, am I correct that there is no penalty? Thank you Ormand but let me be clear about what I asked because it may be confusing; I put it in quotes here again. What I am asking is: 1) If I have a hex with three units of 10 each artillery, e.g., I have 300 stack points in that hex. I "do understand" that if I attack a hex with all this artillery, there is a penalty. If you go over 100 stack BSART "attacking a hex", there is a penalty. 2) What I want to know is if I take this same hex with 3 X 10 artillery, and even though it is 300 stack points, if I now attack three separate hexes with 10 artillery on each hex, am I penalty free? I am not exceeding 100 "BSART" on any one hex that I am attacking, I am laying down 100 on three separate hexes, even though I have 300 stack points where I am attacking "from". I am new and I want to be clear, and if you are clear on your answer it is because I am new that I don't understand. I am trying to differentiate if the "key" is a) the amount of stack points in a hex from which an attack was launched or b) the amount of "stack points" or "BSART" that is laid down on any one hex. I am assuming, and I need to know if I am wrong, that you can stack as many points as you want in any one hex; the penalty comes in if you attack "a hex" with more than 100 points, not the number of stack points in the hex "from which the attack was launched". This is what I need clarified. Thanks again to all for any input.
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