obrien979
Posts: 29
Joined: 5/18/2018 Status: offline
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quote:
ORIGINAL: Dragon029 Radar signature is measured in dBsm, which is a decibel / logarithmic scale. To convert from decibel square metres to normal square metres, you use the formula: area in square metre = 10 ^ (dBsm / 10) Then to convert an area in square metres back into dBsm, you use the formula (where the log is using base 10): area in dBsm = 10 x log(area in square metres) Due to the nature of logarithms and powers, the more negative a value is in dBsm, the smaller an area it represents. So according to that chart (which is going to be speculation or from an incomplete simulation keep in mind), the F-117A has an average radar signature of -14dBsm in radar bands A-D, which roughly equals 0.04m^2, and a radar signature of -24dBsm in radar bands E-M, which roughly equals 0.004m^2. The F-22 meanwhile apparently has an average radar signature in the A-D bands of -20dBsm or 0.01m^2 (4x smaller than the F-117), and an average radar signature in the E-M bands of -30dBsm or 0.001m^2 (again 4x smaller than the F-117). Thank you for this outstanding explanation in Layman's terms. I think I have an understanding of this now. I suspected that the lower the negative value, the better its stealthiness. Time to put this new knowledge to test on some missions.
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BOB
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