Centuur
Posts: 8802
Joined: 6/3/2011 From: Hoorn (NED). Status: offline
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A hex can have one, two or three units defending. However, if you've got a hex with a 3, 4 and 1 factor unit defending in it (totalling 8 ground factors, consisting of two crappy corps and a division), that hex is far better defended than if there would be only one 8 factor unit in it. You empty a hex with one unit, at a die roll of 14 or higher on the 2D10 tables (assault, Blitzkrieg is 13), as compared to 19/16 when there are two units in that hex (three even needs a 20 on the assault table). That's a huge difference. Therefore, any hex which is defended by only one unit is by definition a vulnerable hex. The chance of taking that hex when using the same odds as attacking a hex with 2 or 3 units in it, are more than two times higher. Furthermore, the effect the taking of hexes has got on the overall position of the defender can be quite damaging, since it opens more hexes to be attacked. It's not important to kill a lot of enemy units in an attack. It's far more important to move forward. An attack which doesn't take the hex, is a failed attack, even if you did kill of two defending units, because if the defender has got reserves he can simply move two units into that position and you are faced with the exact same situation next impulse...
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Peter
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