herwin -> RE: 1000 Pounders versus Battleships (2/28/2008 10:08:31 PM)
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ORIGINAL: Shark7 quote:
ORIGINAL: niceguy2005 How many torps did it take to sink all of force Z? Seems to me it is impossible to say how many hits a ship requires to be effectively sunk. Wasn't Hornet essentially done for by the time the last torpedos hit? Took 86 torps to sink all of Force Z, that's the number of G4Ms that attacked it. Of course, only a handfull of those 86 torps actually hit. [:)] And actually all of Force Z didn't sink, the DDs escaped. During most of the war, one in nine air-borne torpedoes launched actually hit, but the early-war IJN pilots were able to double that. The basic idea is that torpedoes or mines sink a ship by destroying its water-tight integrity incrementally--which translates into exposing portions of its water-line area to the open ocean. A torpedo warhead destroys or damages the water-tight integrity of those compartments within a blast radius proportional to the cube root of the warhead weight times the explosive power. Statistics of warship losses in WWII and some post-war studies indicate that a good estimate of the average number of airborne torpedoes required to sink a WWII surface warship was LPPxBeam/10000, with perhaps 70% of that number being required if all the torpedoes hit on one side. WWI designs and carriers were about 2/3rds as resistant to this mode of sinking as WWII-era surface warships. 86 torpedoes launched would suggest about 19-20 hitting. 7 would have been enough for the Prince of Wales and perhaps 4 or 5 for the Repulse. Bubble-bubble. To see where this goes, suppose the US Battle Fleet had moved to Lahaina Roads and the KB had found it and launched a strike. 6x18x2/9 = 24 torpedoes expected to hit. That would have sunk 4-5 of the US BBs or (more likely) seriously damaged about 6, with a couple more sinking. Meanwhile, Pearl was hit by the IJN VBs. I suspect it would have been pucker up time for both sides.
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